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x2+x+100=-x
We move all terms to the left:
x2+x+100-(-x)=0
We add all the numbers together, and all the variables
x2+x-(-1x)+100=0
We add all the numbers together, and all the variables
x^2+x-(-1x)+100=0
We get rid of parentheses
x^2+x+1x+100=0
We add all the numbers together, and all the variables
x^2+2x+100=0
a = 1; b = 2; c = +100;
Δ = b2-4ac
Δ = 22-4·1·100
Δ = -396
Delta is less than zero, so there is no solution for the equation
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