x2+x+1=(x+1)(x-1)

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Solution for x2+x+1=(x+1)(x-1) equation: 



x2+x+1=(x+1)(x-1)

We move all terms to the left:

x2+x+1-((x+1)(x-1))=0

We add all the numbers together, and all the variables

x^2+x-((x+1)(x-1))+1=0

We use the square of the difference formula

x^2+x^2+x+1+1=0

We add all the numbers together, and all the variables

2x^2+x+2=0

a = 2; b = 1; c = +2;
Δ = b2-4ac
Δ = 12-4·2·2
Δ = -15
Delta is less than zero, so there is no solution for the equation

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