x2+x+1=7x2+x+1=7

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Solution for x2+x+1=7x2+x+1=7 equation: 



x2+x+1=7x^2+x+1=7

We move all terms to the left:

x2+x+1-(7x^2+x+1)=0

We add all the numbers together, and all the variables

x^2+x-(7x^2+x+1)+1=0

We get rid of parentheses

x^2-7x^2+x-x-1+1=0

We add all the numbers together, and all the variables

-6x^2=0

a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-12}=0$

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