x2+x+55=x2+4x+5

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Solution for x2+x+55=x2+4x+5 equation: 



x2+x+55=x2+4x+5

We move all terms to the left:

x2+x+55-(x2+4x+5)=0

We add all the numbers together, and all the variables

-(+x^2+4x+5)+x2+x+55=0

We add all the numbers together, and all the variables

x^2-(+x^2+4x+5)+x+55=0

We get rid of parentheses

x^2-x^2-4x+x-5+55=0

We add all the numbers together, and all the variables

-3x+50=0

We move all terms containing x to the left, all other terms to the right

-3x=-50

x=-50/-3

x=16+2/3

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