x2+x=58

Solution for x2+x=58 equation:

x2+x=58

We move all terms to the left:

x2+x-(58)=0

We add all the numbers together, and all the variables

x^2+x-58=0

a = 1; b = 1; c = -58;
Δ = b2-4ac
Δ = 12-4·1·(-58)
Δ = 233
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{233}}{2*1}=\frac{-1-\sqrt{233}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{233}}{2*1}=\frac{-1+\sqrt{233}}{2}
$