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x2-(5x+3)-37=x
We move all terms to the left:
x2-(5x+3)-37-(x)=0
We add all the numbers together, and all the variables
x^2-1x-(5x+3)-37=0
We get rid of parentheses
x^2-1x-5x-3-37=0
We add all the numbers together, and all the variables
x^2-6x-40=0
a = 1; b = -6; c = -40;
Δ = b2-4ac
Δ = -62-4·1·(-40)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-14}{2*1}=\frac{-8}{2} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+14}{2*1}=\frac{20}{2} =10 $
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