x2-(x+1)(x+1)=5

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Solution for x2-(x+1)(x+1)=5 equation: 



x2-(x+1)(x+1)=5

We move all terms to the left:

x2-(x+1)(x+1)-(5)=0

We add all the numbers together, and all the variables

x^2-(x+1)(x+1)-5=0

We multiply parentheses ..

x^2-(+x^2+x+x+1)-5=0

We get rid of parentheses

x^2-x^2-x-x-1-5=0

We add all the numbers together, and all the variables

-2x-6=0

We move all terms containing x to the left, all other terms to the right

-2x=6

x=6/-2

x=-3

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