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x2-0.8x-2.4=0
We add all the numbers together, and all the variables
x^2-0.8x-2.4=0
a = 1; b = -0.8; c = -2.4;
Δ = b2-4ac
Δ = -0.82-4·1·(-2.4)
Δ = 10.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.8)-\sqrt{10.24}}{2*1}=\frac{0.8-\sqrt{10.24}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.8)+\sqrt{10.24}}{2*1}=\frac{0.8+\sqrt{10.24}}{2} $
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