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x2-0.9x+0.2=0
We add all the numbers together, and all the variables
x^2-0.9x+0.2=0
a = 1; b = -0.9; c = +0.2;
Δ = b2-4ac
Δ = -0.92-4·1·0.2
Δ = 0.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.9)-\sqrt{0.01}}{2*1}=\frac{0.9-\sqrt{0.01}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.9)+\sqrt{0.01}}{2*1}=\frac{0.9+\sqrt{0.01}}{2} $
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