If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x2-12x+30=23
We move all terms to the left:
x2-12x+30-(23)=0
We add all the numbers together, and all the variables
x^2-12x+7=0
a = 1; b = -12; c = +7;
Δ = b2-4ac
Δ = -122-4·1·7
Δ = 116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{116}=\sqrt{4*29}=\sqrt{4}*\sqrt{29}=2\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{29}}{2*1}=\frac{12-2\sqrt{29}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{29}}{2*1}=\frac{12+2\sqrt{29}}{2} $
| -g=-2g-10 | | 16-6x=x+19 | | 77+150+48+x=360 | | 10h-4h=12 | | -10+4m=4+2m | | 25=-7u+5(u+7) | | 5(4+p)=12+3p | | 7+n/3=7 | | 10d-10=10d+10+4d | | 144=(3y)^2 | | 2n-4=76 | | 7-6f=-7f | | 8+a/3=10 | | -6v=-8-8v | | -3+m=6-2m | | (x-5)(x+8)=14 | | -y/49+13/49=-40 | | -10p=10-9p | | 10p=10-9p | | -3+m/4=-2 | | -10f-5=-9f | | 12y=5y+8 | | 3-0.25x=-1/2+9 | | 2x=1-5/3 | | 7p-8=6p | | 9v+10=4v | | 34*0.6+x*0.4=40 | | 2(4-8x+6)=-1 | | 8j+5=7j | | 7-5x=-7-3x | | 2(4-8x+6=-1 | | -2y=8-3y |