If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x2-12x+49=22
We move all terms to the left:
x2-12x+49-(22)=0
We add all the numbers together, and all the variables
x^2-12x+27=0
a = 1; b = -12; c = +27;
Δ = b2-4ac
Δ = -122-4·1·27
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6}{2*1}=\frac{6}{2} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6}{2*1}=\frac{18}{2} =9 $
| 36-(-6)=3x+10-x | | 15b+30=90 | | (U+6)^2=2u^2+16u+15 | | -2p-5(2+2p)=6(p-4)-2 | | X/2+x/6=3/2 | | X=45x=-45 | | 8v+24=-2(v-2) | | 5s-2=13 | | 5y-4y-1=2y-1 | | F=5(x-65)+50 | | 9801/x=27 | | 5x-0.5(4-3X)=1.5-(2X+3) | | M^4-m^2+1=0 | | 353.92/e=56 | | 37.1/a=5.3 | | 6d=0.466 | | 4.41/c=0.63 | | 4n+22=18 | | 16x+6x+20-10=46 | | H(t)=-16t^2+40t+160 | | 3(2y+4)=4(3y-8) | | H(t)=-16^2+40t+160 | | 4k+6=2k+18 | | F=1,8c+32 | | w/16+5/6=1 | | 2x(15+2x)=4 | | 12x-4=-3x-58 | | 32x5-3=1 | | 2*3^x+7=25 | | 12a=30 | | 3(x+6)-7=17 | | 24a*23=a+12 |