x2-12x-160=0

Solution for x2-12x-160=0 equation:

x2-12x-160=0

We add all the numbers together, and all the variables

x^2-12x-160=0

a = 1; b = -12; c = -160;
Δ = b2-4ac
Δ = -122-4·1·(-160)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-28}{2*1}=\frac{-16}{2}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+28}{2*1}=\frac{40}{2}
=20
$