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x2-12x-35=0

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Solution for x2-12x-35=0 equation: 



x2-12x-35=0

We add all the numbers together, and all the variables

x^2-12x-35=0

a = 1; b = -12; c = -35;
Δ = b2-4ac
Δ = -122-4·1·(-35)
Δ = 284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

The end solution:


\sqrt{\Delta}=\sqrt{284}=\sqrt{4*71}=\sqrt{4}*\sqrt{71}=2\sqrt{71}


x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{71}}{2*1}=\frac{12-2\sqrt{71}}{2}



x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{71}}{2*1}=\frac{12+2\sqrt{71}}{2}

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