x2-13x+24=0

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Solution for x2-13x+24=0 equation:



x2-13x+24=0
We add all the numbers together, and all the variables
x^2-13x+24=0
a = 1; b = -13; c = +24;
Δ = b2-4ac
Δ = -132-4·1·24
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{73}}{2*1}=\frac{13-\sqrt{73}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{73}}{2*1}=\frac{13+\sqrt{73}}{2} $

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