x2-13x+49=3x+1

Solution for x2-13x+49=3x+1 equation:

x2-13x+49=3x+1

We move all terms to the left:

x2-13x+49-(3x+1)=0

We add all the numbers together, and all the variables

x^2-13x-(3x+1)+49=0

We get rid of parentheses

x^2-13x-3x-1+49=0

We add all the numbers together, and all the variables

x^2-16x+48=0

a = 1; b = -16; c = +48;
Δ = b2-4ac
Δ = -162-4·1·48
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8}{2*1}=\frac{8}{2}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8}{2*1}=\frac{24}{2}
=12
$