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x2-13x=30
We move all terms to the left:
x2-13x-(30)=0
We add all the numbers together, and all the variables
x^2-13x-30=0
a = 1; b = -13; c = -30;
Δ = b2-4ac
Δ = -132-4·1·(-30)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-17}{2*1}=\frac{-4}{2} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+17}{2*1}=\frac{30}{2} =15 $
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