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x2-142x=24
We move all terms to the left:
x2-142x-(24)=0
We add all the numbers together, and all the variables
x^2-142x-24=0
a = 1; b = -142; c = -24;
Δ = b2-4ac
Δ = -1422-4·1·(-24)
Δ = 20260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20260}=\sqrt{4*5065}=\sqrt{4}*\sqrt{5065}=2\sqrt{5065}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-142)-2\sqrt{5065}}{2*1}=\frac{142-2\sqrt{5065}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-142)+2\sqrt{5065}}{2*1}=\frac{142+2\sqrt{5065}}{2} $
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