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x2-15x-250=0
We add all the numbers together, and all the variables
x^2-15x-250=0
a = 1; b = -15; c = -250;
Δ = b2-4ac
Δ = -152-4·1·(-250)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-35}{2*1}=\frac{-20}{2} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+35}{2*1}=\frac{50}{2} =25 $
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