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x2-160x+4.800=0
We add all the numbers together, and all the variables
x^2-160x+4.8=0
a = 1; b = -160; c = +4.8;
Δ = b2-4ac
Δ = -1602-4·1·4.8
Δ = 25580.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-\sqrt{25580.8}}{2*1}=\frac{160-\sqrt{25580.8}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+\sqrt{25580.8}}{2*1}=\frac{160+\sqrt{25580.8}}{2} $
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