x2-17x+50=0

Solution for x2-17x+50=0 equation:

x2-17x+50=0

We add all the numbers together, and all the variables

x^2-17x+50=0

a = 1; b = -17; c = +50;
Δ = b2-4ac
Δ = -172-4·1·50
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{89}}{2*1}=\frac{17-\sqrt{89}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{89}}{2*1}=\frac{17+\sqrt{89}}{2}
$