x2-18x+11=0

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Solution for x2-18x+11=0 equation:



x2-18x+11=0
We add all the numbers together, and all the variables
x^2-18x+11=0
a = 1; b = -18; c = +11;
Δ = b2-4ac
Δ = -182-4·1·11
Δ = 280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{280}=\sqrt{4*70}=\sqrt{4}*\sqrt{70}=2\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{70}}{2*1}=\frac{18-2\sqrt{70}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{70}}{2*1}=\frac{18+2\sqrt{70}}{2} $

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