x2-18x+23=-8x-1

Solution for x2-18x+23=-8x-1 equation:

x2-18x+23=-8x-1

We move all terms to the left:

x2-18x+23-(-8x-1)=0

We add all the numbers together, and all the variables

x^2-18x-(-8x-1)+23=0

We get rid of parentheses

x^2-18x+8x+1+23=0

We add all the numbers together, and all the variables

x^2-10x+24=0

a = 1; b = -10; c = +24;
Δ = b2-4ac
Δ = -102-4·1·24
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2}{2*1}=\frac{8}{2}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2}{2*1}=\frac{12}{2}
=6
$