x2-19x-39=0

Solution for x2-19x-39=0 equation:

x2-19x-39=0

We add all the numbers together, and all the variables

x^2-19x-39=0

a = 1; b = -19; c = -39;
Δ = b2-4ac
Δ = -192-4·1·(-39)
Δ = 517
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{517}}{2*1}=\frac{19-\sqrt{517}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{517}}{2*1}=\frac{19+\sqrt{517}}{2}
$