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x2-2.542=0
We add all the numbers together, and all the variables
x^2-2.542=0
a = 1; b = 0; c = -2.542;
Δ = b2-4ac
Δ = 02-4·1·(-2.542)
Δ = 10.168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{10.168}}{2*1}=\frac{0-\sqrt{10.168}}{2} =-\frac{\sqrt{}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{10.168}}{2*1}=\frac{0+\sqrt{10.168}}{2} =\frac{\sqrt{}}{2} $
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