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x2-2.6x-5=0
We add all the numbers together, and all the variables
x^2-2.6x-5=0
a = 1; b = -2.6; c = -5;
Δ = b2-4ac
Δ = -2.62-4·1·(-5)
Δ = 26.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.6)-\sqrt{26.76}}{2*1}=\frac{2.6-\sqrt{26.76}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.6)+\sqrt{26.76}}{2*1}=\frac{2.6+\sqrt{26.76}}{2} $
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