x2-20x+51=(x+17)(x-3)

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Solution for x2-20x+51=(x+17)(x-3) equation: 



x2-20x+51=(x+17)(x-3)

We move all terms to the left:

x2-20x+51-((x+17)(x-3))=0

We add all the numbers together, and all the variables

x^2-20x-((x+17)(x-3))+51=0

We multiply parentheses ..

x^2-((+x^2-3x+17x-51))-20x+51=0



We calculate terms in parentheses: -((+x^2-3x+17x-51)), so:

(+x^2-3x+17x-51)

We get rid of parentheses

x^2-3x+17x-51

We add all the numbers together, and all the variables

x^2+14x-51

Back to the equation:

-(x^2+14x-51)



We add all the numbers together, and all the variables

x^2-20x-(x^2+14x-51)+51=0

We get rid of parentheses

x^2-x^2-20x-14x+51+51=0

We add all the numbers together, and all the variables

-34x+102=0

We move all terms containing x to the left, all other terms to the right

-34x=-102

x=-102/-34

x=+3

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