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x2-24=300
We move all terms to the left:
x2-24-(300)=0
We add all the numbers together, and all the variables
x^2-324=0
a = 1; b = 0; c = -324;
Δ = b2-4ac
Δ = 02-4·1·(-324)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*1}=\frac{-36}{2} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*1}=\frac{36}{2} =18 $
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