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x2-24x+44=0
We add all the numbers together, and all the variables
x^2-24x+44=0
a = 1; b = -24; c = +44;
Δ = b2-4ac
Δ = -242-4·1·44
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-20}{2*1}=\frac{4}{2} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+20}{2*1}=\frac{44}{2} =22 $
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