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X2-25X-136=0
We add all the numbers together, and all the variables
X^2-25X-136=0
a = 1; b = -25; c = -136;
Δ = b2-4ac
Δ = -252-4·1·(-136)
Δ = 1169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{1169}}{2*1}=\frac{25-\sqrt{1169}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{1169}}{2*1}=\frac{25+\sqrt{1169}}{2} $
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