If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x2-28x-86=0
We add all the numbers together, and all the variables
x^2-28x-86=0
a = 1; b = -28; c = -86;
Δ = b2-4ac
Δ = -282-4·1·(-86)
Δ = 1128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1128}=\sqrt{4*282}=\sqrt{4}*\sqrt{282}=2\sqrt{282}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-2\sqrt{282}}{2*1}=\frac{28-2\sqrt{282}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+2\sqrt{282}}{2*1}=\frac{28+2\sqrt{282}}{2} $
| 3(2x+1=3(x-1)-2(x-3) | | x/(0.3-x)(0.4-x)=4.67 | | X2-32x-136=0 | | 5x-4=3(x-4) | | 5x-4=3(2x-4) | | 7(y+5)=70 | | 3=5x-10 | | (3-x)^2=1 | | 2x+(4x+4)=12x-(6x-7) | | 5x-8=2+x-3 | | X+7=3-(10-x) | | 5(x-8)=2+(x-3) | | x-7=3-(10-x) | | (1,22+2,7x)-(0,48+1,17x)=3,5x-(3,4x-1,01) | | 65=5n | | -12b-2.7=19b-9 | | 20n^2-15n=0 | | 20+x/5=15 | | 4-3y=+6+1 | | 5+3(x+5)=x+6 | | 2(x+1)=4(1-x) | | 1.8*10^(-5)=x^2/0.25-x | | 5x+13=40+2 | | 18=3(2x=4) | | 18x(2x=4) | | 10(s-5)=11 | | 6x-2=2(2x6) | | 10^x=1.89 | | 7-e=12 | | 1x^2-14x+24=0 | | (9-x^2)^3/2=0 | | -14x+24+x^2=0 |