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x2-2x-1.25=0
We add all the numbers together, and all the variables
x^2-2x-1.25=0
a = 1; b = -2; c = -1.25;
Δ = b2-4ac
Δ = -22-4·1·(-1.25)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-3}{2*1}=\frac{-1}{2} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+3}{2*1}=\frac{5}{2} =2+1/2 $
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