x2-2x-10403=0

Solution for x2-2x-10403=0 equation:

x2-2x-10403=0

We add all the numbers together, and all the variables

x^2-2x-10403=0

a = 1; b = -2; c = -10403;
Δ = b2-4ac
Δ = -22-4·1·(-10403)
Δ = 41616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{41616}=204$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-204}{2*1}=\frac{-202}{2}
=-101
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+204}{2*1}=\frac{206}{2}
=103
$