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x2-3.5x+3=0
We add all the numbers together, and all the variables
x^2-3.5x+3=0
a = 1; b = -3.5; c = +3;
Δ = b2-4ac
Δ = -3.52-4·1·3
Δ = 0.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.5)-\sqrt{0.25}}{2*1}=\frac{3.5-\sqrt{0.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.5)+\sqrt{0.25}}{2*1}=\frac{3.5+\sqrt{0.25}}{2} $
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