x2-32x+240=0

Solution for x2-32x+240=0 equation:

x2-32x+240=0

We add all the numbers together, and all the variables

x^2-32x+240=0

a = 1; b = -32; c = +240;
Δ = b2-4ac
Δ = -322-4·1·240
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-8}{2*1}=\frac{24}{2}
=12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+8}{2*1}=\frac{40}{2}
=20
$