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x2-33x+260=0
We add all the numbers together, and all the variables
x^2-33x+260=0
a = 1; b = -33; c = +260;
Δ = b2-4ac
Δ = -332-4·1·260
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-7}{2*1}=\frac{26}{2} =13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+7}{2*1}=\frac{40}{2} =20 $
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