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x2-345x-234=0
We add all the numbers together, and all the variables
x^2-345x-234=0
a = 1; b = -345; c = -234;
Δ = b2-4ac
Δ = -3452-4·1·(-234)
Δ = 119961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{119961}=\sqrt{81*1481}=\sqrt{81}*\sqrt{1481}=9\sqrt{1481}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-345)-9\sqrt{1481}}{2*1}=\frac{345-9\sqrt{1481}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-345)+9\sqrt{1481}}{2*1}=\frac{345+9\sqrt{1481}}{2} $
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