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x2-34x=10
We move all terms to the left:
x2-34x-(10)=0
We add all the numbers together, and all the variables
x^2-34x-10=0
a = 1; b = -34; c = -10;
Δ = b2-4ac
Δ = -342-4·1·(-10)
Δ = 1196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1196}=\sqrt{4*299}=\sqrt{4}*\sqrt{299}=2\sqrt{299}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-2\sqrt{299}}{2*1}=\frac{34-2\sqrt{299}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+2\sqrt{299}}{2*1}=\frac{34+2\sqrt{299}}{2} $
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