x2-35x+150=0

Solution for x2-35x+150=0 equation:

x2-35x+150=0

We add all the numbers together, and all the variables

x^2-35x+150=0

a = 1; b = -35; c = +150;
Δ = b2-4ac
Δ = -352-4·1·150
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-25}{2*1}=\frac{10}{2}
=5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+25}{2*1}=\frac{60}{2}
=30
$