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x2-35x+216=0
We add all the numbers together, and all the variables
x^2-35x+216=0
a = 1; b = -35; c = +216;
Δ = b2-4ac
Δ = -352-4·1·216
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-19}{2*1}=\frac{16}{2} =8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+19}{2*1}=\frac{54}{2} =27 $
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