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x2-36=16x
We move all terms to the left:
x2-36-(16x)=0
We add all the numbers together, and all the variables
x^2-16x-36=0
a = 1; b = -16; c = -36;
Δ = b2-4ac
Δ = -162-4·1·(-36)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-20}{2*1}=\frac{-4}{2} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+20}{2*1}=\frac{36}{2} =18 $
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