x2-3x(2+x)=-x(3+2x)+15

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Solution for x2-3x(2+x)=-x(3+2x)+15 equation: 



x2-3x(2+x)=-x(3+2x)+15

We move all terms to the left:

x2-3x(2+x)-(-x(3+2x)+15)=0

We add all the numbers together, and all the variables

x2-3x(x+2)-(-x(2x+3)+15)=0

We add all the numbers together, and all the variables

x^2-3x(x+2)-(-x(2x+3)+15)=0

We multiply parentheses

x^2-3x^2-6x-(-x(2x+3)+15)=0



We calculate terms in parentheses: -(-x(2x+3)+15), so:

-x(2x+3)+15

We multiply parentheses

-2x^2-3x+15

Back to the equation:

-(-2x^2-3x+15)



We add all the numbers together, and all the variables

-2x^2-(-2x^2-3x+15)-6x=0

We get rid of parentheses

-2x^2+2x^2+3x-6x-15=0

We add all the numbers together, and all the variables

-3x-15=0

We move all terms containing x to the left, all other terms to the right

-3x=15

x=15/-3

x=-5

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