x2-3x/2-5=x-20/4=

Solution for x2-3x/2-5=x-20/4= equation:

x2-3x/2-5=x-20/4=

We move all terms to the left:

x2-3x/2-5-(x-20/4)=0

We add all the numbers together, and all the variables

x2-3x/2-(x-5)-5=0

We add all the numbers together, and all the variables

x^2-3x/2-(x-5)-5=0

We get rid of parentheses

x^2-3x/2-x+5-5=0

We multiply all the terms by the denominator


x^2*2-3x-x*2+5*2-5*2=0

We add all the numbers together, and all the variables

x^2*2-3x-x*2=0

Wy multiply elements

2x^2-3x-2x=0

We add all the numbers together, and all the variables

2x^2-5x=0

a = 2; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·2·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*2}=\frac{10}{4}
=2+1/2
$