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x2-4.6x+5.29=62
We move all terms to the left:
x2-4.6x+5.29-(62)=0
We add all the numbers together, and all the variables
x^2-4.6x-56.71=0
a = 1; b = -4.6; c = -56.71;
Δ = b2-4ac
Δ = -4.62-4·1·(-56.71)
Δ = 248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{248}=\sqrt{4*62}=\sqrt{4}*\sqrt{62}=2\sqrt{62}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.6)-2\sqrt{62}}{2*1}=\frac{4.6-2\sqrt{62}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.6)+2\sqrt{62}}{2*1}=\frac{4.6+2\sqrt{62}}{2} $
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