x2-400x+2400=0

Solution for x2-400x+2400=0 equation:

x2-400x+2400=0

We add all the numbers together, and all the variables

x^2-400x+2400=0

a = 1; b = -400; c = +2400;
Δ = b2-4ac
Δ = -4002-4·1·2400
Δ = 150400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{150400}=\sqrt{1600*94}=\sqrt{1600}*\sqrt{94}=40\sqrt{94}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-400)-40\sqrt{94}}{2*1}=\frac{400-40\sqrt{94}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-400)+40\sqrt{94}}{2*1}=\frac{400+40\sqrt{94}}{2}
$