x2-41x+400=0

Solution for x2-41x+400=0 equation:

x2-41x+400=0

We add all the numbers together, and all the variables

x^2-41x+400=0

a = 1; b = -41; c = +400;
Δ = b2-4ac
Δ = -412-4·1·400
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-9}{2*1}=\frac{32}{2}
=16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+9}{2*1}=\frac{50}{2}
=25
$