x2-45x-216=0

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Solution for x2-45x-216=0 equation:



x2-45x-216=0
We add all the numbers together, and all the variables
x^2-45x-216=0
a = 1; b = -45; c = -216;
Δ = b2-4ac
Δ = -452-4·1·(-216)
Δ = 2889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2889}=\sqrt{9*321}=\sqrt{9}*\sqrt{321}=3\sqrt{321}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-3\sqrt{321}}{2*1}=\frac{45-3\sqrt{321}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+3\sqrt{321}}{2*1}=\frac{45+3\sqrt{321}}{2} $

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