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x2-4x+4=-x2+6x-8
We move all terms to the left:
x2-4x+4-(-x2+6x-8)=0
We add all the numbers together, and all the variables
-(-1x^2+6x-8)+x2-4x+4=0
We add all the numbers together, and all the variables
x^2-(-1x^2+6x-8)-4x+4=0
We get rid of parentheses
x^2+1x^2-6x-4x+8+4=0
We add all the numbers together, and all the variables
2x^2-10x+12=0
a = 2; b = -10; c = +12;
Δ = b2-4ac
Δ = -102-4·2·12
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2}{2*2}=\frac{8}{4} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2}{2*2}=\frac{12}{4} =3 $
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