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X2-4X-396=0
We add all the numbers together, and all the variables
X^2-4X-396=0
a = 1; b = -4; c = -396;
Δ = b2-4ac
Δ = -42-4·1·(-396)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-40}{2*1}=\frac{-36}{2} =-18 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+40}{2*1}=\frac{44}{2} =22 $
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