x2-50x+600=0

Solution for x2-50x+600=0 equation:

x2-50x+600=0

We add all the numbers together, and all the variables

x^2-50x+600=0

a = 1; b = -50; c = +600;
Δ = b2-4ac
Δ = -502-4·1·600
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-10}{2*1}=\frac{40}{2}
=20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+10}{2*1}=\frac{60}{2}
=30
$