x2-5x=-5(x-10)

Solution for x2-5x=-5(x-10) equation:

x2-5x=-5(x-10)

We move all terms to the left:

x2-5x-(-5(x-10))=0

We add all the numbers together, and all the variables

x^2-5x-(-5(x-10))=0


We calculate terms in parentheses: -(-5(x-10)), so:

-5(x-10)

We multiply parentheses

-5x+50

Back to the equation:

-(-5x+50)


We get rid of parentheses

x^2-5x+5x-50=0

We add all the numbers together, and all the variables

x^2-50=0

a = 1; b = 0; c = -50;
Δ = b2-4ac
Δ = 02-4·1·(-50)
Δ = 200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{200}=\sqrt{100*2}=\sqrt{100}*\sqrt{2}=10\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{2}}{2*1}=\frac{0-10\sqrt{2}}{2}
=-\frac{10\sqrt{2}}{2}
=-5\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{2}}{2*1}=\frac{0+10\sqrt{2}}{2}
=\frac{10\sqrt{2}}{2}
=5\sqrt{2}
$